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Two students find the mean of the same grouped data by the assumed mean method, one taking a = 25 and the other a = 35. Their answers ____.

Class 10StatisticsStatistics and Probability
  • Aare exactly equal
  • Bdiffer by 10
  • Cdiffer by 10 divided by the class width
  • Dcannot be compared unless both use the same a

Step-by-Step Solution

The assumed mean is only a computing device: a + Σfd/Σf always collapses back to Σfx/Σf whatever a is. Changing a shifts every d by the same amount and the correction term absorbs that shift exactly, so both students obtain the identical mean.
Answer: A) are exactly equal

Key idea: Mean by assumed mean and step-deviation

**Assumed mean**: pick a value 'a' close to the centre. Compute deviations dᵢ = ᵢ − a.

**Formula**: **̄ = + Σ(fᵢdᵢ) / Σfᵢ**

This simplifies arithmetic when class marks are large.

**Step-deviation method**: when all class widths equal , define uᵢ = ᵢ − a)/.

**Formula**: **̄ = × [Σ(fᵢuᵢ) / Σfᵢ]**

This turns class marks into small integers (e.g., −2, −1, 0, 1, 2) — much easier arithmetic.

**All three methods give the same mean** — choose by convenience.

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