A rectangular garden in Jaipur has length 4 m more than its width.
Its perimeter is 36 m, so 2(L + W) = 36 with L = W + 4.
Using substitution, find the width (in metres).

Question

A rectangular garden in Jaipur has length 4 m more than its width. Its perimeter is 36 m, so 2(L + W) = 36 with L = W + 4. Using substitution, find the width (in metres).

Accepted Answer

7. 2(L + W) = 36 means L + W = 18. Substitute L = W + 4: (W + 4) + W = 18, 2W = 14, W = 7 m.

A rectangular garden in Jaipur has length 4 m more than its width.
Its perimeter is 36 m, so 2(L + W) = 36 with L = W + 4.
Using substitution, find the width (in metres).

Step-by-Step Solution

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More Class 10 Substitution Method practice

A rectangular garden in Jaipur has length 4 m more than its width.Its perimeter is 36 m, so 2(L + W) = 36 with L = W + 4.Using substitution, find the width (in metres).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Substitution Method practice

A rectangular garden in Jaipur has length 4 m more than its width.
Its perimeter is 36 m, so 2(L + W) = 36 with L = W + 4.
Using substitution, find the width (in metres).