A two-digit number's digits are the roots of $x^{2} - 9 x + 18 = 0$ .
The tens digit is the smaller root and the units digit is the larger root.
What is the two-digit number?

Question

A two-digit number's digits are the roots of x^2 - 9x + 18 = 0. The tens digit is the smaller root and the units digit is the larger root. What is the two-digit number?

Accepted Answer

36. x^2 - 9x + 18 = (x-3)(x-6) = 0, roots 3 and 6. Tens = 3, units = 6, number = 36.

A two-digit number's digits are the roots of $x^{2} - 9 x + 18 = 0$ .
The tens digit is the smaller root and the units digit is the larger root.
What is the two-digit number?

Step-by-Step Solution

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More Class 10 Sum and Product of Roots practice

A two-digit number's digits are the roots of x2−9x+18=0.The tens digit is the smaller root and the units digit is the larger root.What is the two-digit number?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Sum and Product of Roots practice

A two-digit number's digits are the roots of $x^{2} - 9 x + 18 = 0$ .
The tens digit is the smaller root and the units digit is the larger root.
What is the two-digit number?