Two cones share a common circular base (a bicone), each of base radius 0.7 cm; the upper cone has slant height 3 cm and the lower cone slant height 5 cm. The total surface area (no base, since it is internal) in cm^2 (π = 22/7) is:

Question

Accepted Answer

17.6 cm^2. Surface = π*r*l1 + π*r*l2 = π*r*(l1+l2) = (22/7)*0.7*(3+5) = (22/7)*0.7*8 = 2.2*8 = 17.6 cm^2.

Two cones share a common circular base (a bicone), each of base radius 0.7 cm; the upper cone has slant height 3 cm and the lower cone slant height 5 cm. The total surface area (no base, since it is internal) in $cm^{2}$ (π = $\frac{22}{7}$ ) is:

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More Class 10 Surface Area of Combined Solids practice

Two cones share a common circular base (a bicone), each of base radius 0.7 cm; the upper cone has slant height 3 cm and the lower cone slant height 5 cm. The total surface area (no base, since it is internal) in cm2 (π = 722​) is:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Surface Area of Combined Solids practice

Two cones share a common circular base (a bicone), each of base radius 0.7 cm; the upper cone has slant height 3 cm and the lower cone slant height 5 cm. The total surface area (no base, since it is internal) in $cm^{2}$ (π = $\frac{22}{7}$ ) is: