Two solid cones of equal base radius 3 cm and slant height 5 cm are joined base to base (a 'double cone' or bicone). The total surface area of the resulting solid is: (Take π = 22/7)

Question

Accepted Answer

660/7 cm^2. The two circular bases vanish. Surface = 2 * (π*r*l) = 2*(22/7)*3*5 = 660/7 cm^2 (approx 94.3 cm^2).

Two solid cones of equal base radius 3 cm and slant height 5 cm are joined base to base (a 'double cone' or bicone). The total surface area of the resulting solid is: (Take π = $\frac{22}{7}$ )

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More Class 10 Surface Area of Combined Solids practice

Two solid cones of equal base radius 3 cm and slant height 5 cm are joined base to base (a 'double cone' or bicone). The total surface area of the resulting solid is: (Take π = 722​)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Surface Area of Combined Solids practice

Two solid cones of equal base radius 3 cm and slant height 5 cm are joined base to base (a 'double cone' or bicone). The total surface area of the resulting solid is: (Take π = $\frac{22}{7}$ )