- A50°
- B40°
- C80°
- D100°
Step-by-Step Solution
OP bisects ∠APB, so ∠OPA = 40°. In right triangle OAP (∠OAP = 90°), ∠AOP = 180° − 90° − 40° = 50°.
Answer: A) 50°
Tangents PA and PB are drawn to a circle with centre O and ∠APB = 80°. Find ∠AOP.
Class 10Tangent Lengths and IncirclesGeometry
Master this chapter in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Tangent Lengths and Incircles practice questions
More Class 10 Tangent Lengths and Incircles practice
Tangents PA and PB are drawn from P, and the chord AB makes ∠PAB = 65°. Find ∠APB.Tanu has a circle of radius 3 cm and a tangent PA = 4 cm. She writes OP = 3 + 4 = 7 cm.…A square is drawn around a circle of radius 6 cm so that every side touches the circle.…Quadrilateral ABCD circumscribes a circle with AB = 3x cm, BC = (2x + 1) cm, CD = 10 cm…Two tangents from P to a circle of radius 5 cm are inclined to each other at 60°. How…