The diagonal of a rectangular field is 60 m more than the shorter side, and the longer side is 30 m more than the shorter side. With shorter side x, this gives x^2 - 60x - 2700 = 0. Find the shorter side in metres.

Question

Accepted Answer

90. Diagonal d = x + 60, longer side = x + 30. Then x^2 + (x+30)^2 = (x+60)^2 => x^2 + x^2 + 60x + 900 = x^2 + 120x + 3600 => x^2 - 60x - 2700 = 0. x = 60 ± √3600 + 108002 = 60 ± 120/2 = 90. Shorter side = 90 m.

The diagonal of a rectangular field is 60 m more than the shorter side, and the longer side is 30 m more than the shorter side.
With shorter side $x$ , this gives $x^{2} - 60 x - 2700 = 0$ .
Find the shorter side in metres.

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More Class 10 The Quadratic Formula practice

The diagonal of a rectangular field is 60 m more than the shorter side, and the longer side is 30 m more than the shorter side.With shorter side x, this gives x2−60x−2700=0.Find the shorter side in metres.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

The diagonal of a rectangular field is 60 m more than the shorter side, and the longer side is 30 m more than the shorter side.
With shorter side $x$ , this gives $x^{2} - 60 x - 2700 = 0$ .
Find the shorter side in metres.