The hypotenuse of a right triangle is 13 cm. The other two sides differ by 7 cm.
Letting the shorter side be $x$ , we get $x^{2} + 7 x - 60 = 0$ .
Find the shorter side in cm.

Question

The hypotenuse of a right triangle is 13 cm. The other two sides differ by 7 cm. Letting the shorter side be x, we get x^2 + 7x - 60 = 0. Find the shorter side in cm.

Accepted Answer

5. x^2 + (x+7)^2 = 13^2 gives 2x^2 + 14x - 120 = 0, i.e. x^2 + 7x - 60 = 0. x = -7 ± √49 + 2402 = -7 ± 17/2 = 5. Sides 5 and 12.

The hypotenuse of a right triangle is 13 cm. The other two sides differ by 7 cm.
Letting the shorter side be $x$ , we get $x^{2} + 7 x - 60 = 0$ .
Find the shorter side in cm.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

The hypotenuse of a right triangle is 13 cm. The other two sides differ by 7 cm.Letting the shorter side be x, we get x2+7x−60=0.Find the shorter side in cm.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

The hypotenuse of a right triangle is 13 cm. The other two sides differ by 7 cm.
Letting the shorter side be $x$ , we get $x^{2} + 7 x - 60 = 0$ .
Find the shorter side in cm.