Rekha buys an item for ₹x and sells it for ₹1200, making a profit of x percent. This gives x^2 + 100x - 120000 = 0. What did she pay for the item?

Question

Accepted Answer

₹300. Selling price = x + x/100 × x = 1200 => x^2 + 100x - 120000 = 0. D = 10000 + 480000 = 490000, √D = 700. x = -100 ± 700/2 = 300 or -400. Cost = ₹300 (profit 300% of ₹300 = ₹900, total ₹1200).

Rekha buys an item for ₹ $x$ and sells it for ₹1200, making a profit of $x$ percent.
This gives $x^{2} + 100 x - 120000 = 0$ . What did she pay for the item?

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More Class 10 The Quadratic Formula practice

Rekha buys an item for ₹x and sells it for ₹1200, making a profit of x percent.This gives x2+100x−120000=0. What did she pay for the item?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

Rekha buys an item for ₹ $x$ and sells it for ₹1200, making a profit of $x$ percent.
This gives $x^{2} + 100 x - 120000 = 0$ . What did she pay for the item?