The diagonal of a rectangular field is 60 m more than the shorter side. The longer side is 30 m more than the shorter side. Taking the shorter side as x, this gives x^2 - 60x - 2700 = 0. Find the shorter side (m) using the quadratic formula.

Question

Accepted Answer

90. By Pythagoras: (x + 60)^2 = x^2 + (x + 30)^2 => x^2 + 120x + 3600 = x^2 + x^2 + 60x + 900 => x^2 - 60x - 2700 = 0. D = 3600 + 10800 = 14400, √D = 120. x = 60 ± 120/2 = 90 or -30. Shorter side = 90 m.

The diagonal of a rectangular field is 60 m more than the shorter
side. The longer side is 30 m more than the shorter side. Taking the
shorter side as $x$ , this gives $x^{2} - 60 x - 2700 = 0$ .
Find the shorter side (m) using the quadratic formula.

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More Class 10 The Quadratic Formula practice

The diagonal of a rectangular field is 60 m more than the shorterside. The longer side is 30 m more than the shorter side. Taking theshorter side as x, this gives x2−60x−2700=0.Find the shorter side (m) using the quadratic formula.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 The Quadratic Formula practice

The diagonal of a rectangular field is 60 m more than the shorter
side. The longer side is 30 m more than the shorter side. Taking the
shorter side as $x$ , this gives $x^{2} - 60 x - 2700 = 0$ .
Find the shorter side (m) using the quadratic formula.