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In Δ and Δ and ∠ = ∠. A student concludes Δ ~ Δ by SAS. Is the conclusion justified?

Class 10Triangles (Similarity)Geometry — Similarity
  • ANo — ∠B is not the angle included between AB and AC, so this is the SSA pattern, which does not prove similarity
  • BYes — any equal pair of angles together with two proportional sides is enough
  • CYes — because the third pair of sides BC and EF must then also be proportional
  • DNo — the ratio of the sides must be 1 for similarity

Step-by-Step Solution

The two proportional sides are AB and AC, whose included angle is ∠A, not ∠B. Using ∠B here gives the SSA arrangement, which fails for similarity just as it fails for congruence. Had ∠A = ∠D been given instead, SAS would apply. A ratio of 1 is not required — that would force congruence, not similarity.
Answer: A) No — ∠B is not the angle included between AB and AC, so this is the SSA pattern, which does not prove similarity

Key idea: Three similarity criteria

**AA (Angle-Angle)**: Two angles equal → similar. (Third angle is automatic by 180° angle sum.)

**SSS (Side-Side-Side proportionality)**: All three pairs of corresponding sides in same ratio → similar.

**SAS (Side-Angle-Side)**: Two pairs of sides proportional AND included angles equal → similar.

**Important**: SSA does NOT prove similarity (just like for congruence).

AA is by far the most-used in problems: spot two equal angles (often via parallel lines or shared angle) and declare similarity.

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