A revision sheet asks for $\frac{\cos A}{1-\tan A}+\frac{\sin A}{1-\cot A}$ as one simple expression.
Which is it?

Write $1-\tan A=\frac{\cos A-\sin A}{\cos A}$ and $1-\cot A=\frac{\sin A-\cos A}{\sin A}$. The sum becomes $\frac{{\cos }^{2}A}{\cos A-\sin A}+\frac{{\sin }^{2}A}{\sin A-\cos A}=\frac{{\cos }^{2}A-{\sin }^{2}A}{\cos A-\sin A}=\cos A+\sin A$. Missing the sign flip in the second denominator is exactly what produces $\sin A-\cos A$. Check at $A=60$ deg: the sum is about 1.366, and $\sin 60^{\circ }+\cos 60^{\circ }\approx 1.366$.