If A = 1/3 for an acute angle A, find A + A .

√2. A + A = 1/ A + A/ A = 1 + A/ A . Here A = √1 - 19 = 2√23 , so the value is 4/32√2/3 = 42√2 = √2 . Answering 4/3 stops at the numerator 1 + A and never divides by A .

If $sin A = \frac{1}{3}$ for an acute angle A, find $sec A + tan A$ .

Class 10Trigonometric IdentitiesTrigonometry

A $\frac{4}{3}$
B $2$
C $\frac{1}{2}$
D $22$

Step-by-Step Solution

sec A + tan A = \frac{1}{c o s A} + \frac{s i n A}{c o s A} = \frac{1 + s i n A}{c o s A}

. Here

cos A = 1 - \frac{1}{9} = \frac{2 2}{3}

, so the value is

\frac{4/3}{2 2 /3} = \frac{4}{2 2} = 2

. Answering

\frac{4}{3}

stops at the numerator

1 + sin A

and never divides by

cos A

Answer: B)

2

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If sinA=31​ for an acute angle A, find secA+tanA.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Trigonometric Identities practice

If $sin A = \frac{1}{3}$ for an acute angle A, find $sec A + tan A$ .