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If sec A + tan A = 3, a competitive-exam coaching class in Jaipur asks for the value of sec A - tan A.

Class 10Trigonometric IdentitiesTrigonometry

A $\frac{1}{3}$
B3
C1
D $\frac{1}{9}$

Step-by-Step Solution

Since (sec A + tan A)(sec A - tan A) = se

c^{2}

A - ta

n^{2} A = 1

, we have (sec A - tan A) =

\frac{1}{s e c A + t a n A} = \frac{1}{3}

.

Answer: A)

\frac{1}{3}

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