A cone of radius 5 cm and height 8 cm is cut by a plane parallel to the base, halfway up the height, removing the small top cone. Find the volume of the remaining frustum (use π = 3.14, answer in cm^3 to two decimals).

Question

Accepted Answer

183.17. Full cone = (1/3)(3.14)(25)(8) = 3.14 × 200/3 = 628/3 = 209.33. Top small cone: at half height, radius scales to 2.5 cm, height 4 cm; volume = (1/3)(3.14)(6.25)(4) = 3.14 × 25/3 = 78.5/3 = 26.17. Frustum = 209.33 - 26.17 = 183.17 cm^3.

A cone of radius 5 cm and height 8 cm is cut by a plane parallel to the base, halfway up the height, removing the small top cone.
Find the volume of the remaining frustum (use π = 3.14, answer in $cm^{3}$ to two decimals).

Step-by-Step Solution

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More Class 10 Volume of Combined Solids practice

A cone of radius 5 cm and height 8 cm is cut by a plane parallel to the base, halfway up the height, removing the small top cone.Find the volume of the remaining frustum (use π = 3.14, answer in cm3 to two decimals).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Volume of Combined Solids practice

A cone of radius 5 cm and height 8 cm is cut by a plane parallel to the base, halfway up the height, removing the small top cone.
Find the volume of the remaining frustum (use π = 3.14, answer in $cm^{3}$ to two decimals).