Meera's present age is 3 years less than twice Sahil's present age. Four years from now their ages will add up to 41 years. How old is Meera now?

Let Meera be $x$ and Sahil $y$ years old. $x=2y-3$ and $(x+4)+(y+4)=41$, so $x+y=33$. Substituting, $3y-3=33,y=12$ and $x=21$. Check: 21 = 24 - 3, and 25 + 16 = 41. 12 years is Sahil's age; 24 years is twice Sahil's age with the '3 less' dropped; 25 years is Meera's age four years from now.