If alpha and beta are the zeroes of x^2 - 3x - 10, then a quadratic polynomial whose zeroes are (1/alpha) and (1/beta) is (with integer coefficients):

Question

Accepted Answer

10x^2 + 3x - 1. Sum = 3, product = -10. New sum = alpha+beta/alpha · beta = 3/-10 = -3/10. New product = 1/alpha · beta = -1/10. Poly = x^2 - (-3/10)x + (-1/10) = x^2 + 3/10x - 1/10; multiply by 10: 10x^2 + 3x - 1.

If alpha and beta are the zeroes of $x^{2} - 3 x - 10$ , then a quadratic polynomial whose zeroes are (1/alpha) and (1/beta) is (with integer coefficients):

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Zeroes and Coefficients practice

If alpha and beta are the zeroes of x2−3x−10, then a quadratic polynomial whose zeroes are (1/alpha) and (1/beta) is (with integer coefficients):

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Zeroes and Coefficients practice

If alpha and beta are the zeroes of $x^{2} - 3 x - 10$ , then a quadratic polynomial whose zeroes are (1/alpha) and (1/beta) is (with integer coefficients):