For the polynomial p(x) = 6x^2 - 7x - 3, one zero is 3/2. What is the other zero?

-1/3. Product of zeroes = c/a = -3/6 = -1/2. Other zero = -1/2/3/2 = -1/3. Check: 6(1/9) - 7(-1/3) - 3 = 2/3 + 7/3 - 3 = 3 - 3 = 0.

For the polynomial $p (x) = 6 x^{2} - 7 x - 3$ , one zero is $\frac{3}{2}$ .
What is the other zero?

Class 10Zeroes of a PolynomialAlgebra — Polynomials

Product of zeroes =

\frac{c}{a} = \frac{- 3}{6} = - \frac{1}{2}

. Other zero =

\frac{- 1/2}{3/2} = - \frac{1}{3}

. Check:

6 (\frac{1}{9}) - 7 (- \frac{1}{3}) - 3 = \frac{2}{3} + \frac{7}{3} - 3 = 3 - 3 = 0

Answer: A)

- \frac{1}{3}

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