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Three integers are added in a row: the first is -8, the second is twice the additive inverse of -8, and the third is -25.
What is the sum of the three integers?
(The additive inverse of -8 is 8.)

Class 6Addition of IntegersIntegers
  • A-16
  • B-18
  • C-34
  • D-17

Step-by-Step Solution

Additive inverse of -8 is 8, twice that is 16. Sum: -8 + 16 + (-25) = 8 + (-25) = -17.
Answer: D) -17

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