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Solve the equation p − 3 = 9 by inspection.

Class 6AlgebraAlgebra
  • A12
  • B6
  • C27
  • D3

Step-by-Step Solution

We need a number that leaves 9 after 3 is taken away. Try 12: 12 − 3 = 9 ✓. The trap 6 does 9 − 3 instead of asking what number the subtraction started from; 27 multiplies 9 by 3.
Answer: A) 12

Key idea: From expressions to equations

Add an equals sign and you have an **equation** — a question. 'For what value of does equal 13?' is written . The **solution** is the value that makes the two sides equal. Here, works, because . For Class 6, the simplest method is **trial-and-improvement** — try whole numbers until you find one that works. Faster algebraic methods come in Class 7.

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