A path 2 m wide runs all around the inside edge of a rectangular field 40 m by 30 m. The path follows the boundary; the inner rectangle is the leftover central area. What is the area of the inner central rectangle (not the path)?

Question

Accepted Answer

936. A 2 m path inside all four edges removes 4 m from each dimension. Inner length = 40 - 4 = 36 m, inner width = 30 - 4 = 26 m. Inner area = 36 x 26 = 936 sq m.

A path 2 m wide runs all around the inside edge of a rectangular field 40 m by 30 m.
The path follows the boundary; the inner rectangle is the leftover central area.
What is the area of the inner central rectangle (not the path)?

Step-by-Step Solution

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More Class 6 Area of Rectangles and Squares practice

A path 2 m wide runs all around the inside edge of a rectangular field 40 m by 30 m.The path follows the boundary; the inner rectangle is the leftover central area.What is the area of the inner central rectangle (not the path)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 6 Area of Rectangles and Squares practice

A path 2 m wide runs all around the inside edge of a rectangular field 40 m by 30 m.
The path follows the boundary; the inner rectangle is the leftover central area.
What is the area of the inner central rectangle (not the path)?