- AIt is also divisible by 3
- BIt is also divisible by 2
- CIt is also divisible by 5
- DIt must be even
Step-by-Step Solution
Since , every multiple of 9 is also a multiple of 3. So any number divisible by 9 is automatically divisible by 3. The others need not hold (e.g. 27 is odd and not divisible by 2 or 5).
Answer: A) It is also divisible by 3