- ADivisible by 3
- BDivisible by 2
- CDivisible by 12
- DDivisible by both 2 and 3
Step-by-Step Solution
The shaded squares are 6, 12, 18, 24, … — every 6th number. These are even AND have a digit sum that is a multiple of 3. Multiples of 3 alone would include 3 and 9; even numbers alone would include 2 and 4; multiples of 12 would leave out 6 and 18.
Answer: D) Divisible by both 2 and 3