Practice30Create account

Which number is divisible by both 4 and 9?

Class 6Divisibility RulesPlaying with Numbers
  • A216
  • B224
  • C234
  • D248

Step-by-Step Solution

For 4, the last two digits must be divisible by 4; for 9, the digit sum must be a multiple of 9. 216: (passes 4) and 2 + 1 + 6 = 9 (passes 9). So 216 is divisible by both.
Answer: A) 216

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Divisibility Rules practice questions

More Class 6 Divisibility Rules practice

What is the smallest digit that can replace * in 2,3*5 so that the number is divisible…Aarav has 96 marbles. He wants to share them equally with no marble left over. Which of…A shopkeeper has a three-digit number of cookies written as 5A6, where A is a single…In a school assembly, students stand in rows. There are 132 students. They can stand in…A number is divisible by 2 and by 3. Meena claims it must also be divisible by 6. Is…