Practice30 Create account

Find the greatest number of 3 digits which is exactly divisible by 8, 10 and 12.

Class 6HCF and LCMPlaying with Numbers

A1920
B1055
C960
D865

Step-by-Step Solution

LCM(8,10,12):

8 = 2^{3}, 10 = 2 \times 5, 12 = 2^{2} x 3

, LCM =

2^{3} x 3 x 5 = 120

. Greatest 3-digit multiple of 120:

120 \times 8 = 960 (120 \times 9 = 1080

is 4-digit).

Answer: C) 960

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All HCF and LCM practice questions

More Class 6 HCF and LCM practice

Find the least number which when increased by 7 is exactly divisible by 12, 16 and 18.The LCM of two co-prime numbers is 117. One of the numbers is 9. What is the other number?Three bells in a school ring at intervals of 9, 12 and 15 minutes. They all ring…The factor tree shows 84. Also, 60 = 2 × 2 × 3 × 5 . Using the prime factors, what is…A hall floor in Lucknow is drawn on the grid. It must be covered with identical square…