- AP is less than −4 and S is greater than 1
- BP is greater than −4 and S is greater than 1
- CP and S are both negative
- DP is −5 and S is 2
Step-by-Step Solution
P stands to the left of Q, so P < −4, and S stands to the right of R, so S > 1. That is everything the picture forces. S must in fact be positive, and neither P nor S is pinned to one particular value, so the other options can all fail.
Answer: A) P is less than −4 and S is greater than 1