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A marker starts at 90 on a number line and jumps left.
Its jumps are 1, 2, 3, 4, ... steps long (each jump one longer than the last).
After how many jumps does it first reach 0 or go past it (to the left)?

Class 6Number Line OperationsWhole Numbers
  • A11
  • B12
  • C13
  • D14

Step-by-Step Solution

Sum 1+2+...+n must be at least 90. 1+...+12 = 78 (still at 12, not yet 90); 1+...+13 = 91, which is past 90, so after 13 jumps it is at 90 - 91 = below 0. The answer is 13.
Answer: C) 13

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