- A6
- B7
- C8
- D12
Step-by-Step Solution
50 - 8 = 42 = , so 6 left-jumps of 7 land exactly on 8, needing no right jumps. That is the least: 6 jumps.
Answer: A) 6
Deepak stands at 50 on a number line.
He must reach 8 using only jumps of 7 to the left and jumps of 1 to the right.
What is the least total number of jumps he needs?
Class 6Number Line OperationsWhole Numbers
Master this chapter in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Number Line Operations practice questions
More Class 6 Number Line Operations practice
Two markers start together at 0. Marker P jumps right in steps of 9; Marker Q jumps…Sita starts at 100 on a number line and jumps left in steps of 7. Vijay starts at 0 and…A robot starts at 0 on a number line. Its move pattern is +10, -3, +10, -3, ...…A number line measures a road in metres. A cyclist at 0 rides forward (right) 8 m, back…M is the midpoint of 8 and 32 on a number line. From M a marker makes 3 equal jumps to…