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Consider three-digit numbers in which the middle digit equals the sum of the first and last digits.
For example, in 132 the middle digit 3 = 1 + 2, and in 165 the middle digit 6 = 1 + 5.
How many such three-digit numbers have first digit 1 (that is, of the form 1, m, last with m = 1 + last)?

Class 6Patterns and RulesAlgebra
  • A8
  • B9
  • C10
  • D11

Step-by-Step Solution

First digit 1, last digit d from 0 to 8 (so middle = 1 + d no more than 9). d = 0,1,...,8 gives 9 numbers: 110, 121, 132, ..., 198.
Answer: B) 9

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