1. Riya's square handkerchief has each side 25 cm. What is its perimeter?
- A50 cm
- B75 cm
- C100 cm
- D625 cm
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Answer: C) 100 cm
Perimeter of a square = 4 × side = 4 × 25 = 100 cm.
Class 6 Perimeter Word Problems — practice questions with answers
Mensuration · 5 sample questions from the school syllabus. Try each one, then open the answer and the worked solution.
2. The cost of fencing a square plot at ₹20 per metre is ₹2400. What is the side of the plot?
- A30 m
- B40 m
- C60 m
- D120 m
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Answer: A) 30 m
Perimeter = 2400 ÷ 20 = 120 m. Side = 120 ÷ 4 = 30 m.
3. The length of a rectangle is twice its breadth. If the breadth is 14 cm, what is the perimeter?
- A56 cm
- B84 cm
- C42 cm
- D392 cm
Show answer
Answer: B) 84 cm
Length = 2 × 14 = 28 cm. Perimeter = 2 × (28 + 14) = 2 × 42 = 84 cm.
4. A square handkerchief of side 30 cm is folded once along its middle to form a rectangle.
What is the perimeter of the folded rectangle?
What is the perimeter of the folded rectangle?
- A60 cm
- B90 cm
- C120 cm
- D45 cm
Show answer
Answer: B) 90 cm
Folding gives a rectangle of length 30 cm and breadth 15 cm (half of 30). Perimeter = 2 × (30 + 15) = 90 cm.
5. A regular hexagonal park has each side 45 m.
A jogger completes 2 full rounds of it.
The path is then to be lit with lamps placed every 18 m along the single boundary, starting from a corner.
How many lamps are needed for one boundary?
A jogger completes 2 full rounds of it.
The path is then to be lit with lamps placed every 18 m along the single boundary, starting from a corner.
How many lamps are needed for one boundary?
- A10
- B15
- C18
- D30
Show answer
Answer: B) 15
Boundary perimeter = 6 × 45 = 270 m. Lamps every 18 m around a closed boundary = 270 ÷ 18 = 15 lamps.
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