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Six identical steel tumblers weigh 1 kg 320 g altogether. What is the total weight of 11 such tumblers?

Class 6Ratio and ProportionRatio and Proportion
  • A220 g
  • B2 kg 200 g
  • C14 kg 520 g
  • D2 kg 420 g

Step-by-Step Solution

Write the weight in one unit first: 1 kg 320 g = 1320 g. One tumbler = 1320 ÷ 6 = 220 g, so 11 tumblers weigh g = 2 kg 420 g. Stopping at 220 g gives only one tumbler; 14 kg 520 g scales the six-tumbler weight instead of the one-tumbler weight; 2 kg 200 g is 10 tumblers.
Answer: D) 2 kg 420 g

Key idea: Unitary method

If 5 pens cost ₹40, what do 8 pens cost? Step 1 — find the price of **one** pen: ₹40 ÷ 5 = ₹8. Step 2 — multiply by the new count: 8 × ₹8 = ₹64. The unitary method works for any 'X-many of something costs Y, what about Z-many?' problem. It's just two steps: find the unit, then scale.

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