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Around point O there is a right angle, an angle $x$ and an angle $x + 40$ °. Find $x$ .

Class 7Angles Around a PointLines and Angles

A95°
B155°
C115°
D135°

Step-by-Step Solution

90° +

x + (x + 40

°) = 360°, so

2 x + 130

° = 360°,

2 x = 230

°,

x = 115

°. (155° is

x + 40

°, the other angle.)

Answer: C) 115°

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