Two equal circles, each of radius 7 cm, are drawn so that the centre of each lies on the boundary of the other, overlapping in the middle. What is the combined area of the two full circles (counting the overlap twice, i.e. the simple sum of both areas)? (Take π = 22/7)

Question

Accepted Answer

308. Each circle has area 22/7*7*7 = 154 cm^2. The simple sum of both areas = 154 + 154 = 308 cm^2.

Two equal circles, each of radius 7 cm, are drawn so that the centre of each lies on the boundary of the other, overlapping in the middle.
What is the combined area of the two full circles (counting the overlap twice, i.e. the simple sum of both areas)? (Take π = $\frac{22}{7}$ )

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More Class 7 Area of a Circle practice

Two equal circles, each of radius 7 cm, are drawn so that the centre of each lies on the boundary of the other, overlapping in the middle.What is the combined area of the two full circles (counting the overlap twice, i.e. the simple sum of both areas)? (Take π = 722​)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Area of a Circle practice

Two equal circles, each of radius 7 cm, are drawn so that the centre of each lies on the boundary of the other, overlapping in the middle.
What is the combined area of the two full circles (counting the overlap twice, i.e. the simple sum of both areas)? (Take π = $\frac{22}{7}$ )