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Rohit found the area of a 1 $m$ path outside a 12 $m \times 8 m$ lawn as $2 \times (12 + 8) \times 1 = 40 m^{2}$ . What did he miss?

Class 7Area of Paths and BordersPerimeter and Area

ANothing; $40 m^{2}$ is right
BHe counted the width twice; $20 m^{2}$
CThe 4 corners; $44 m^{2}$
DThe corners; $36 m^{2}$

Step-by-Step Solution

His strips cover the sides but not the four 1 m × 1 m corners. Correct:

14 \times 10 - 96 = 44 m^{2} = 40 + 4

.

Answer: C) The 4 corners;

44 m^{2}

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