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After a 15% price rise, a motorcycle now costs ₹92000. What was its price before the rise?

Class 7Comparing QuantitiesComparing Quantities
  • A₹78200
  • B₹77000
  • C₹80000
  • D₹105800

Step-by-Step Solution

The rise was 15% OF THE OLD PRICE, so the new price is 115% of it: , giving . Check: 15% of 80000 = 12000, and 80000 + 12000 = 92000. ₹78200 is the trap of taking 15% off the ₹92000 — the percentage belongs to the old price, not the new one. ₹105800 raises the price a second time, and ₹77000 treats 15% as ₹15000.
Answer: C) ₹80000

Key idea: Reading the question carefully

Three things to check before you compute:

1. **What's being asked?** Profit % needs CP and SP. SI needs P, R, T.
2. **What units are the inputs in?** Time in months → convert to years (divide by 12). Rate already per annum → leave it.
3. **What's the base of the percentage?** Profit/loss % is on COST price, not selling price. Discount % is on MARKED price, not on what you actually paid.

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