A craftsman in Moradabad cuts a triangular brass plate. He extends each of the three sides one way and measures the three exterior angles (one per vertex): they are 4x, 5x and 6x degrees. Find the largest exterior angle.

Question

Accepted Answer

144. Sum of one exterior angle per vertex = 360. 4x + 5x + 6x = 15x = 360, x = 24. Largest = 6x = 144°.

A craftsman in Moradabad cuts a triangular brass plate. He extends each of the three sides one way and measures the three exterior angles (one per vertex): they are $4 x, 5 x$ and $6 x$ degrees. Find the largest exterior angle.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Exterior Angle Property practice

A craftsman in Moradabad cuts a triangular brass plate. He extends each of the three sides one way and measures the three exterior angles (one per vertex): they are 4x,5x and 6x degrees. Find the largest exterior angle.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Exterior Angle Property practice

A craftsman in Moradabad cuts a triangular brass plate. He extends each of the three sides one way and measures the three exterior angles (one per vertex): they are $4 x, 5 x$ and $6 x$ degrees. Find the largest exterior angle.