A two-digit number has tens digit t and units digit u, so its value is (10t + u). For the number 74, t = 7 and u = 4. If we reverse the digits, the new value is (10u + t). Find the value of (10t + u) - (10u + t) for the number 74.

Question

Accepted Answer

27. Original 10t + u = 70 + 4 = 74. Reversed 10u + t = 40 + 7 = 47. (10t + u) - (10u + t) = 74 - 47 = 27 (which equals 9(t - u) = 9(7 - 4) = 27).

A two-digit number has tens digit $t$ and units digit $u$ , so its value is $(10 t + u)$ .
For the number 74, $t = 7$ and $u = 4$ . If we reverse the digits, the new value is $(10 u + t)$ .
Find the value of $(10 t + u) - (10 u + t)$ for the number 74.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Finding the Value of an Expression practice

A two-digit number has tens digit t and units digit u, so its value is (10t+u).For the number 74, t=7 and u=4. If we reverse the digits, the new value is (10u+t).Find the value of (10t+u)−(10u+t) for the number 74.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Finding the Value of an Expression practice

A two-digit number has tens digit $t$ and units digit $u$ , so its value is $(10 t + u)$ .
For the number 74, $t = 7$ and $u = 4$ . If we reverse the digits, the new value is $(10 u + t)$ .
Find the value of $(10 t + u) - (10 u + t)$ for the number 74.