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Simplify completely and express as a single power of 2:
$(2^{5} \times 4^{3}) / 8^{2}$
(Hint: write 4 and 8 as powers of 2.)

Class 7Laws of ExponentsNumber System

A $2^{5}$
B $2^{11}$
C $2^{2}$
D $2^{8}$

Step-by-Step Solution

4^{3} = (2^{2})^{3} = 2^{6}

and

8^{2} = (2^{3})^{2} = 2^{6}

. Numerator:

2^{5} \times 2^{6} = 2^{11}

. Then

2^{11} / 2^{6} = 2^{11 - 6} = 2^{5}

.

Answer: A)

2^{5}

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