Rahul draws triangle ABC where median AD is also drawn. He notes AB = 6 cm, AC = 6 cm, BC = 8 cm and finds AD. The median AD here is also the altitude. Find AD^2 (in sq cm).

Question

Accepted Answer

20. Since AB = AC, AD is perpendicular and bisects BC, so BD = 4. AD^2 = AB^2 - BD^2 = 36 - 16 = 20 sq cm.

Rahul draws triangle ABC where median $A D$ is also drawn. He notes AB = 6 cm, AC = 6 cm, BC = 8 cm and finds $A D$ . The median $A D$ here is also the altitude.
Find $A D^{2}$ (in sq cm).

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More Class 7 Medians and Altitudes practice

Rahul draws triangle ABC where median AD is also drawn. He notes AB = 6 cm, AC = 6 cm, BC = 8 cm and finds AD. The median AD here is also the altitude.Find AD2 (in sq cm).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Medians and Altitudes practice

Rahul draws triangle ABC where median $A D$ is also drawn. He notes AB = 6 cm, AC = 6 cm, BC = 8 cm and finds $A D$ . The median $A D$ here is also the altitude.
Find $A D^{2}$ (in sq cm).