A toy car moves along the line at a steady 3 units to the left each second, i.e. −3 units per second, and is at 0 now. Treating time in the past as negative, where was the car when the video is rewound by the time shown?

Question

Accepted Answer

12. Position = speed × time = (-3) × (-4) = 12. Four seconds ago the car was 12 units to the right of 0 — a negative times a negative is positive.

A toy car moves along the line at a steady 3 units to the left each second, i.e. −3 units per second, and is at 0 now. Treating time in the past as negative, where was the car when the video is rewound by the time shown?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Multiplication of Integers practice