Sneha compares two numbers: A = 6 x 10^5 and B = 9 x 10^4. How many times larger (approximately, as a whole number) is A than B? Round to the nearest whole number.

Question

Accepted Answer

7. A/B = (6 x 10^5)/(9 x 10^4) = 6/9 x 10^(5-4) = 0.6667 x 10 = 6.67, which rounds to 7.

Sneha compares two numbers: $A = 6 \times 1 0^{5}$ and $B = 9 \times 1 0^{4}$ .
How many times larger (approximately, as a whole number) is A than $B$ ? Round to the nearest whole number.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Powers of 10 practice

Sneha compares two numbers: A=6×105 and B=9×104.How many times larger (approximately, as a whole number) is A than B? Round to the nearest whole number.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Powers of 10 practice

Sneha compares two numbers: $A = 6 \times 1 0^{5}$ and $B = 9 \times 1 0^{4}$ .
How many times larger (approximately, as a whole number) is A than $B$ ? Round to the nearest whole number.