A tailor in Surat has a red ribbon of 120 cm (2^3 × 3 × 5) and a blue ribbon of 180 cm (2^2 × 3^2 × 5). He cuts both into pieces of equal length, as long as possible, with nothing left over. How long is each piece?

Question

Accepted Answer

60 cm. Longest equal piece = HCF = smaller exponent of each common prime: 2^2 × 3 × 5 = 60 cm. (360 cm is the LCM, longer than either ribbon.)

A tailor in Surat has a red ribbon of 120 cm $(2^{3} \times 3 \times 5)$ and a blue ribbon of 180 cm $(2^{2} \times 3^{2} \times 5)$ . He cuts both into pieces of equal length, as long as possible, with nothing left over. How long is each piece?

Step-by-Step Solution

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More Class 7 Prime Factors in Exponent Form practice

A tailor in Surat has a red ribbon of 120 cm (23×3×5) and a blue ribbon of 180 cm (22×32×5). He cuts both into pieces of equal length, as long as possible, with nothing left over. How long is each piece?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Prime Factors in Exponent Form practice

A tailor in Surat has a red ribbon of 120 cm $(2^{3} \times 3 \times 5)$ and a blue ribbon of 180 cm $(2^{2} \times 3^{2} \times 5)$ . He cuts both into pieces of equal length, as long as possible, with nothing left over. How long is each piece?