At Lucknow bus stand, one bus leaves every 12 minutes (2^2 × 3) and another every 18 minutes (2 × 3^2). Both leave together at 8:00. After how many minutes will they next leave together?

Question

Accepted Answer

36 minutes. We need the LCM: take each prime with its larger exponent, 2^2 × 3^2 = 36. So after 36 minutes (at 8:36). 6 is the HCF; 216 is 12 × 18.

At Lucknow bus stand, one bus leaves every 12 minutes $(2^{2} \times 3)$ and another every 18 minutes $(2 \times 3^{2})$ . Both leave together at 8:00. After how many minutes will they next leave together?

Step-by-Step Solution

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More Class 7 Prime Factors in Exponent Form practice

At Lucknow bus stand, one bus leaves every 12 minutes (22×3) and another every 18 minutes (2×32). Both leave together at 8:00. After how many minutes will they next leave together?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 7 Prime Factors in Exponent Form practice

At Lucknow bus stand, one bus leaves every 12 minutes $(2^{2} \times 3)$ and another every 18 minutes $(2 \times 3^{2})$ . Both leave together at 8:00. After how many minutes will they next leave together?