Class 7 Rational Numbers on the Number Line — practice questions with answers

Rational Numbers · 5 sample questions from the school syllabus. Try each one, then open the answer and the worked solution.

1. Into how many equal parts must the segment between 0 and 1 be divided to mark the rational number

\frac{3}{5}

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Answer: B) 5

The denominator tells the number of equal parts. For

\frac{3}{5}

, divide 0 to 1 into 5 equal parts;

\frac{3}{5}

is the 3rd mark.

2. Arrange on the number line from left to right:

- \frac{1}{2}

\frac{1}{4}

- \frac{3}{4}

, 0. Which number is the leftmost?

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Answer: C)

- \frac{3}{4}

- \frac{3}{4}

= -0.75 is the most negative, so it lies farthest to the left.

3. On the number line, which statement about

- \frac{2}{5}

and

\frac{1}{5}

is correct?

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Answer: B)

\frac{1}{5}

lies right of

- \frac{2}{5}

\frac{1}{5}

is positive and

- \frac{2}{5}

is negative, so

\frac{1}{5}

lies to the right of

- \frac{2}{5}

4. The figure shows a number line from 0 to 2 split into halves. Identify the rational number marked at point T.

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Answer: B)

\frac{3}{2}

From 0 to 2 in halves the marks are

\frac{1}{2}

, 1,

\frac{3}{2}

. T is at the third small mark, which is

\frac{3}{2}

5. Three runners stand on a track marked as a number line: Anu at

- \frac{7}{6}

, Bina at

- \frac{1}{2}

, Charu at

\frac{5}{6}

.
Who is exactly at the midpoint between the positions of Anu and Charu?

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Answer: C) no one; midpoint is

- \frac{1}{6}

Midpoint of

- \frac{7}{6}

and

\frac{5}{6}

\frac{- \frac{7}{6} + \frac{5}{6}}{2} = \frac{- \frac{2}{6}}{2} = \frac{- \frac{1}{3}}{2} = - \frac{1}{6}

. Bina is at

- \frac{1}{2}

, not

- \frac{1}{6}

, so no one stands there.

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