At a Diwali party a packet of 76 sweets is shared equally among 8 children, and 4 sweets are left over. How many sweets did each child get?

Let each child get s sweets. The 8 shares plus the 4 left over make the whole packet: 8s + 4 = 76 → 8s = 72 → s = 9. Check: 8(9) + 4 = 76 ✓. Answer 10 adds the 4 leftover sweets instead of setting them aside; 72 stops before dividing by 8; 8 repeats the number of children instead of the share.