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The formula for the sum of interior angles of a polygon with n sides is:

Class 8Angle Sum of PolygonsQuadrilaterals

A $(n - 2) \times 180$ deg
Bn $x$ 180°
C $(n - 2) \times 90$ deg
D $\frac{360}{n}$ deg

Step-by-Step Solution

A polygon of

n

sides splits into

(n - 2)

triangles, each contributing 180°, giving

(n - 2) \times 180

deg.

Answer: A)

(n - 2) \times 180

deg

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