The area of a field shaped like a quadrilateral is 1750 sq m. A diagonal of 70 m divides it into two triangles; the perpendicular from one vertex onto this diagonal is 28 m. Find the perpendicular from the opposite vertex onto the same diagonal.

Question

Accepted Answer

22 m. Area = 1/2 d (h1+h2). 1750 = 1/2(70)(28+h2) = 35(28+h2). So 28+h2 = 50, h2 = 22 m.

The area of a field shaped like a quadrilateral is 1750 sq m. A diagonal of 70 m divides it into two triangles; the perpendicular from one vertex onto this diagonal is 28 m.
Find the perpendicular from the opposite vertex onto the same diagonal.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Area of Polygons practice

The area of a field shaped like a quadrilateral is 1750 sq m. A diagonal of 70 m divides it into two triangles; the perpendicular from one vertex onto this diagonal is 28 m.Find the perpendicular from the opposite vertex onto the same diagonal.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Area of Polygons practice

The area of a field shaped like a quadrilateral is 1750 sq m. A diagonal of 70 m divides it into two triangles; the perpendicular from one vertex onto this diagonal is 28 m.
Find the perpendicular from the opposite vertex onto the same diagonal.