A trapezium ABCD has AB parallel to DC, with AB = 7 cm, DC = 4 cm, angle A = 90° and the height (perpendicular distance) AD = 4 cm. What is the length of the slant side BC? (Hint: drop a perpendicular from C to AB.)

Question

Accepted Answer

5. Drop CE perpendicular to AB, with E on AB. Then AE = DC = 4, so EB = AB - AE = 7 - 4 = 3, and CE = AD = 4. In right triangle CEB, BC = √EB^2 + CE^2 = √3^2 + 4^2 = √9 + 16 = √25 = 5 cm.

A trapezium ABCD has AB parallel to DC, with AB = 7 cm, DC = 4 cm, angle A = 90° and the height (perpendicular distance) AD = 4 cm.
What is the length of the slant side BC?
(Hint: drop a perpendicular from C to AB.)

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More Class 8 Constructing Quadrilaterals practice

A trapezium ABCD has AB parallel to DC, with AB = 7 cm, DC = 4 cm, angle A = 90° and the height (perpendicular distance) AD = 4 cm.What is the length of the slant side BC?(Hint: drop a perpendicular from C to AB.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Constructing Quadrilaterals practice

A trapezium ABCD has AB parallel to DC, with AB = 7 cm, DC = 4 cm, angle A = 90° and the height (perpendicular distance) AD = 4 cm.
What is the length of the slant side BC?
(Hint: drop a perpendicular from C to AB.)