Two dice are rolled. Find P(sum is greater than 9).

Class 8Data HandlingData Handling

Step-by-Step Solution

Sums > 9 are 10, 11, 12. Pairs: (4,6),(5,5),(6,4),(5,6),(6,5),(6,6) = 6 outcomes.

P = \frac{6}{36} = \frac{1}{6}

Answer: A) 1/6

**Theoretical**:

P = \frac{f a v o u r ab l e}{t o t a l}

, assuming all outcomes equally likely.

P

(heads on a fair coin) =

\frac{1}{2}

.

**Experimental**:

P = \frac{t im ese v e n t occ u rre d}{t o t a lt r ia l s}

. After 100 coin tosses with 47 heads, experimental

P

(heads) =

\frac{47}{100} = 0.47

.

Law of large numbers (informally): the more trials you

r u n

, the closer experimental probability gets to theoretical probability. So

\frac{47}{100}

is plausible;

\frac{47}{1 , 000 , 000}

would be very unusual for a fair coin.

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