A grain of fine sand has a mass of about 4 × 10^-8 kg. Written as an ordinary decimal number, how many zeros lie between the decimal point and the digit 4?

Question

Accepted Answer

7. 4 × 10^-8 = 0.00000004 kg. The 4 occupies the 8th decimal place, so only 7 zeros come before it. Copying the power 8 as the number of zeros is the trap — the eighth place holds the digit 4 itself.

A grain of fine sand has a mass of about $4 \times 1 0^{- 8}$ kg. Written as an ordinary decimal number, how many zeros lie between the decimal point and the digit 4?

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More Class 8 Exponents and Powers practice

A grain of fine sand has a mass of about 4×10−8 kg. Written as an ordinary decimal number, how many zeros lie between the decimal point and the digit 4?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Exponents and Powers practice

A grain of fine sand has a mass of about $4 \times 1 0^{- 8}$ kg. Written as an ordinary decimal number, how many zeros lie between the decimal point and the digit 4?